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A person is standing 18 m away from a water tank. The angle of elevation from the person's eye level to the top of the tank is 45 degrees. Calculate the height 'h' of the water tank.

Mathematics

ScanSolve AI Answer

Answer

18 m\text{18 m}

Step-by-step solution

4 steps
  1. Identify the known values and the unknown.

    We have a right-angled triangle where:

    • The angle of elevation (θ\theta) is 45∘45^\circ.
    • The adjacent side (distance from observer to tower) is 18 m18 \text{ m}.
    • The opposite side (height of the tower, hh) is unknown.
  2. Choose the appropriate trigonometric ratio.

    The tangent function relates the opposite side and the adjacent side to the angle:

    tan⁡(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}
  3. Substitute the known values into the formula.

    tan⁡(45∘)=h18 m\tan(45^\circ) = \frac{h}{18 \text{ m}}
  4. Solve for hh.

    We know that tan⁡(45∘)=1\tan(45^\circ) = 1.

    1=h18 m1 = \frac{h}{18 \text{ m}}

    Multiply both sides by 18 m18 \text{ m}:

    h=1×18 mh = 1 \times 18 \text{ m} h=18 mh = 18 \text{ m}
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