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A tower is 42 m away from an observation point. The angle of elevation to the top of the tower from the observation point is 36 degrees. What is the height of the tower?

Mathematics

ScanSolve AI Answer

Answer

30.51 m\text{30.51 m}

Step-by-step solution

6 steps
  1. Identify the known values and the unknown value.

    • The angle of elevation (θ\theta) is 36∘36^\circ. (Assuming "360" is a typo and should be 36∘36^\circ, as 360∘360^\circ would imply the point is directly above the base, not 42 m42 \text{ m} away).
    • The distance from the base of the tower (adjacent side) is 42 m42 \text{ m}.
    • The height of the tower (opposite side) is hh.
  2. Choose the appropriate trigonometric ratio.

    The tangent function relates the opposite side, the adjacent side, and the angle:

    tan⁡(θ)=oppositeadjacent\tan(\theta) = \frac{\text{opposite}}{\text{adjacent}}
  3. Substitute the given values into the formula.

    tan⁡(36∘)=h42\tan(36^\circ) = \frac{h}{42}
  4. Solve for hh.

    Multiply both sides by 42:

    h=42×tan⁡(36∘)h = 42 \times \tan(36^\circ)
  5. Calculate the value of hh.

    Using a calculator for tan⁡(36∘)\tan(36^\circ):

    tan⁡(36∘)≈0.7265\tan(36^\circ) \approx 0.7265 h=42×0.7265h = 42 \times 0.7265 h≈30.513 mh \approx 30.513 \text{ m}
  6. Round the answer to a reasonable number of decimal places (e.g., two decimal places).

    h≈30.51 mh \approx 30.51 \text{ m}

    The height of the tower is:

    30.51 m\text{30.51 m}
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