A viewer is at the top of a 45m tower. The angle of depression to the roof of a house 15m away is 60°. Find the height of the house.

Here's the solution to question 14:

Given:
Height of view tower AB = 45 m
Distance from tower to house BD = 15 m
Angle of depression from the top of the tower (A) to the roof of the house (C) = 60°

Let's draw a horizontal line CE from the roof of the house (C) to the tower (AB), such that E is on AB.
Then, BCDE forms a rectangle.
Therefore, the horizontal distance EC = BD = 15 m.
The height of the house CD = BE.

In the right-angled triangle AEC:
The angle of depression from A to C is 60°. If we draw a horizontal line from A, say AX,