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Three numbers form a GP. If the first and third numbers are 5 and 245 respectively, find two possible values for the middle number.

Mathematics

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Answer

35 and −3535 \text{ and } -35

Step-by-step solution

4 steps

Let the three numbers in the Geometric Progression (GP) be aa, arar, and ar2ar^2, where aa is the first term and rr is the common ratio.

  1. Identify the given values.

    The first term is a=5a = 5.
    The third term is ar2=245ar^2 = 245.

  2. Substitute the value of aa into the equation for the third term to find the common ratio rr.

    5r2=2455r^2 = 245

    Divide both sides by 5:

    r2=2455r^2 = \frac{245}{5} r2=49r^2 = 49
  3. Solve for rr.

    Take the square root of both sides:

    r=±49r = \pm\sqrt{49} r=±7r = \pm 7

    There are two possible values for the common ratio: r=7r=7 and r=−7r=-7.

  4. Calculate the middle number (arar) for each possible value of rr.

    Case 1: If r=7r = 7
    The middle number is ar=5×7=35ar = 5 \times 7 = 35.

    Case 2: If r=−7r = -7
    The middle number is ar=5×(−7)=−35ar = 5 \times (-7) = -35.

    The two possible values for the middle number are 35 and −3535 \text{ and } -35.

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