This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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3 stepsAnswer
25$, Frequency: 9
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To draw a histogram, we first need to adjust the class boundaries to make them continuous. Since the data is given in discrete intervals (e.g., 0-24, 25-49), there's a gap of 1 unit between the upper limit of one class and the lower limit of the next. We adjust this by subtracting 0.5 from the lower limit and adding 0.5 to the upper limit of each class.
Step 1: Adjust class boundaries and determine class width. The adjusted class boundaries and frequencies are: • 0-24: Adjusted class: , Class width: , Frequency: 9 • 25-49: Adjusted class: , Class width: , Frequency: 14 • 50-74: Adjusted class: , Class width: , Frequency: 7 • 75-99: Adjusted class: , Class width: , Frequency: 6 • 100-124: Adjusted class: , Class width: , Frequency: 8 • 125-149: Adjusted class: , Class width: , Frequency: 10 • 150-174: Adjusted class: , Class width: , Frequency: 6
Since all class widths are equal (25 km), the height of each bar in the histogram will be directly proportional to its frequency.
Step 2: Draw the histogram.
Here's a description of the bars you would draw: • Bar 1: Base from to , Height: 9 • Bar 2: Base from to , Height: 14 • Bar 3: Base from to , Height: 7 • Bar 4: Base from to , Height: 6 • Bar 5: Base from to , Height: 8 • Bar 6: Base from to , Height: 10 • Bar 7: Base from to , Height: 6
This will create the required histogram.
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This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.