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The table shows the numbers of cases of Corona Virus registered in Uganda between March, 2020 and June, 2021. Draw a frequency distribution table, a graph of cumulative frequencies, and estimate the median.

Mathematics

ScanSolve AI Answer

Answer

26

Step-by-step solution

6 steps
  1. Determine the total number of cases.

    Add the frequencies:

    14+15+20+14+9+5+2+1+1=8114 + 15 + 20 + 14 + 9 + 5 + 2 + 1 + 1 = 81

    Total cases, N=81N = 81.

  2. Identify the median position.

    The median is the N+12\frac{N+1}{2}th value:

    81+12=41\frac{81 + 1}{2} = 41

    The 41st case.

  3. Construct the cumulative frequency (cf) table using upper class boundaries.

    Classes: 0−90-9, 10−1910-19, 20−2920-29, 30−3930-39, 40−4940-49, 50−5950-59, 60−6960-69, 70−7970-79, 80+80+.
    Upper boundaries: 10, 20, 30, 40, 50, 60, 70, 80, 90.

    Classfcf0−9141410−19152920−29204930−39146340−4997250−5957760−6927970−7918080+181\begin{array}{c|c|c} \text{Class} & f & \text{cf} \\ \hline 0{-}9 & 14 & 14 \\ 10{-}19 & 15 & 29 \\ 20{-}29 & 20 & 49 \\ 30{-}39 & 14 & 63 \\ 40{-}49 & 9 & 72 \\ 50{-}59 & 5 & 77 \\ 60{-}69 & 2 & 79 \\ 70{-}79 & 1 & 80 \\ 80+ & 1 & 81 \\ \end{array}
  4. Draw the cumulative frequency polygon (ogive).

    Plot points: $(10,14)$, $(20,29)$, $(30,49)$, $(40,63)$, $(50,72)$, $(60,77)$, $(70,79)$, $(80,80)$, $(90,81)$.
    Join with straight lines.

  5. Locate the median on the graph.

    Draw horizontal line at cf =41= 41.
    It intersects the line segment from (20,29)(20, 29) to (30,49)(30, 49).

  6. Calculate the median value.

    Formula for intersection:

    x=L+M−cfprevcf−cfprev×wx = L + \frac{M - \text{cf}_{prev}}{ \text{cf} - \text{cf}_{prev} } \times w

    where L=20L = 20 (upper boundary of previous class),
    M=41M = 41 (median position),
    cfprev=29\text{cf}_{prev} = 29,
    cf−cfprev=49−29=20\text{cf} - \text{cf}_{prev} = 49 - 29 = 20,
    w=30−20=10w = 30 - 20 = 10 (class width).

    Substitute:

    x=20+41−2920×10x = 20 + \frac{41 - 29}{20} \times 10 x=20+1220×10x = 20 + \frac{12}{20} \times 10 x=20+0.6×10x = 20 + 0.6 \times 10 x=20+6=26x = 20 + 6 = 26

    (c) Explanation: The ogive is plotted with cumulative frequencies against upper class boundaries. The horizontal line at cf =41= 41 intersects the ogive between upper boundaries 20 and 30. The x-coordinate of the intersection gives the estimated median of 26 cases.

    26

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