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Calculate the total surface area of a cone with a slant height of 6.3 m and a base diameter of 7.2 m.

Mathematics

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Answer

35.64π m235.64\pi \text{ m}^2

111.97 m2111.97 \text{ m}^2

Step-by-step solution

5 steps
  1. Identify the given values.

    The slant height is l=6.3 ml = 6.3 \text{ m}.
    The diameter of the base is d=7.2 md = 7.2 \text{ m}.

  2. Calculate the radius of the base.

    The radius is half of the diameter:

    r=d2=7.2 m2=3.6 mr = \frac{d}{2} = \frac{7.2 \text{ m}}{2} = 3.6 \text{ m}
  3. Write down the formula for the total surface area of a cone.

    The total surface area (TSA) of a cone is given by the formula:

    TSA=πr(r+l)TSA = \pi r (r+l)
  4. Substitute the given values into the formula.

    Substitute r=3.6 mr = 3.6 \text{ m} and l=6.3 ml = 6.3 \text{ m} into the formula:

    TSA=π(3.6 m)(3.6 m+6.3 m)TSA = \pi (3.6 \text{ m}) (3.6 \text{ m} + 6.3 \text{ m})
  5. Calculate the total surface area.

    TSA=π(3.6 m)(9.9 m)TSA = \pi (3.6 \text{ m}) (9.9 \text{ m}) TSA=35.64π m2TSA = 35.64\pi \text{ m}^2

    If we use π≈3.14159\pi \approx 3.14159:

    TSA≈35.64×3.14159 m2TSA \approx 35.64 \times 3.14159 \text{ m}^2 TSA≈111.97 m2TSA \approx 111.97 \text{ m}^2

    The total surface area of the cone is 35.64π m2\boxed{35.64\pi \text{ m}^2} or approximately 111.97 m2\boxed{111.97 \text{ m}^2}.

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