This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
5:45 p.m.
Here are the solutions to the problems.
: Step 1: Find the prime factorization of each interval. The intervals are 9 minutes, 15 minutes, and 21 minutes.
Step 2: Calculate the Least Common Multiple (LCM) of the intervals. The LCM represents the time in minutes after which all bells will ring together again.
Step 3: Convert the LCM from minutes to hours and minutes.
Step 4: The bells will next ring together at 11:00 p.m. To find when they last rang together, subtract the LCM from 11:00 p.m. Converting back to 12-hour format: The bells had last rang together at .
: Step 1: Calculate the nominal area of the rectangle. Length Width Nominal Area .
Step 2: Determine the maximum possible dimensions due to the 5% error. The error in each measurement is 5%. Maximum length . Maximum width .
Step 3: Calculate the maximum possible area.
Step 4: Calculate the maximum absolute error in the area.
Step 5: Calculate the maximum percentage error in the area. The maximum percentage error in the area of the rectangle is .
: Step 1: Use the property that the sum of an interior angle and its corresponding exterior angle of a polygon is . Given interior angle Given exterior angle
Step 2: Solve the equation for .
Step 3: Calculate the measure of the exterior angle. Exterior angle .
Step 4: Find the number of sides () of the polygon. For a regular polygon, the sum of the exterior angles is , and each exterior angle is . The number of sides of the polygon is .
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Find the prime factorization of each interval. The intervals are 9 minutes, 15 minutes, and 21 minutes.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.