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Two families, A and B bought oranges, mangoes and bananas in two weeks as shown in the following tables. (a) Form matrices to represent the information provided. (b) Determine the total number of fruits of each type bought by each family.

Mathematics

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here are the solutions to the problems:

Unnumbered Problem (System of Equations):
The given system of equations is:

  1. 4b+3p=3154b + 3p = 315
  2. 8b+2p=5308b + 2p = 530

Step 1: Multiply equation (1) by 2 to eliminate bb.

2(4b+3p)=2(315)2(4b + 3p) = 2(315) 8b+6p=630(Equation 3)8b + 6p = 630 \quad \text{(Equation 3)}

Step 2: Subtract equation (2) from equation (3).

(8b+6p)−(8b+2p)=630−530(8b + 6p) - (8b + 2p) = 630 - 530 4p=1004p = 100

Step 3: Solve for pp.

p=1004p = \frac{100}{4} p=25p = 25

Step 4: Substitute the value of pp into equation (1).

4b+3(25)=3154b + 3(25) = 315 4b+75=3154b + 75 = 315 4b=315−754b = 315 - 75 4b=2404b = 240

Step 5: Solve for bb.

b=2404b = \frac{240}{4} b=60b = 60

The cost of a book is Ksh 60 and the cost of a pen is Ksh 25.
The final answer is Book: Ksh 60, Pen: Ksh 25\boxed{\text{Book: Ksh 60, Pen: Ksh 25}}.

Part 17

Part a

Form matrices to represent the information provided.

Let M1M_1 be the matrix for Week 1 and M2M_2 be the matrix for Week 2.

M1=[71559203]M_1 = \begin{bmatrix} 7 & 15 & 5 \\ 9 & 20 & 3 \end{bmatrix} M2=[610414152]M_2 = \begin{bmatrix} 6 & 10 & 4 \\ 14 & 15 & 2 \end{bmatrix}

The final answer is M1=[71559203],M2=[610414152]\boxed{M_1 = \begin{bmatrix} 7 & 15 & 5 \\ 9 & 20 & 3 \end{bmatrix}, M_2 = \begin{bmatrix} 6 & 10 & 4 \\ 14 & 15 & 2 \end{bmatrix}}.

Part b· 2 steps

Determine the total number of fruits of each type bought by each family.

To find the total number of fruits, we add the matrices M1M_1 and M2M_2.

  1. Add the corresponding elements of the matrices.

    Mtotal=M1+M2=[71559203]+[610414152]M_{total} = M_1 + M_2 = \begin{bmatrix} 7 & 15 & 5 \\ 9 & 20 & 3 \end{bmatrix} + \begin{bmatrix} 6 & 10 & 4 \\ 14 & 15 & 2 \end{bmatrix}
  2. Perform the addition.

    Mtotal=[7+615+105+49+1420+153+2]M_{total} = \begin{bmatrix} 7+6 & 15+10 & 5+4 \\ 9+14 & 20+15 & 3+2 \end{bmatrix} Mtotal=[1325923355]M_{total} = \begin{bmatrix} 13 & 25 & 9 \\ 23 & 35 & 5 \end{bmatrix}

    This matrix shows:
    For Family A: 13 Oranges, 25 Mangoes, 9 Bananas.
    For Family B: 23 Oranges, 35 Mangoes, 5 Bananas.
    The final answer is [1325923355]\boxed{\begin{bmatrix} 13 & 25 & 9 \\ 23 & 35 & 5 \end{bmatrix}}.

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