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Find two integers r and s such that their product is 6 and their sum is 5.

May 24, 2026Mathematics

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Answer

2 \text{ and } 3

Here is the completed table:

Factors of 6	Product of the two factors	Sum of the two factors	Result
1 and 6	$1 \times 6 = 6$	$1 + 6 = 7$	Product = 6 but sum $\neq$ 5
-1 and -6	$(-1) \times (-6) = 6$	$(-1) + (-6) = -7$	Product = 6 but sum $\neq$ 5
2 and 3	$2 \times 3 = 6$	$2 + 3 = 5$	Product = 6 and sum = 5
-2 and -3	$(-2) \times (-3) = 6$	$(-2) + (-3) = -5$	Product = 6 but sum $\neq$ 5

The two integers, $r$ and $s$ , are $\boxed{2 \text{ and } 3}$ .

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