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Find two integers, r and s, such that their product is -12 and their sum is 1.

Mathematics

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Answer

−3 and 4-3 \text{ and } 4

Step-by-step solution

2 steps
  1. List all pairs of integers whose product is −12-12.

    We are looking for two integers, rr and ss, such that their product r×s=−12r \times s = -12 and their sum r+s=1r + s = 1 (from the previous problem x2+x−12x^2 + x - 12, where c=−12c = -12 and b=1b = 1).

  2. Calculate the product and sum for each pair of factors.

    Fill in the table with the factors of −12-12, their products, and their sums. Mark the pair that results in a sum of 1.

    Factors of -12Product of the two factorsSum of the two factorsResult
    1,−121, -121×(−12)=−121 \times (-12) = -121+(−12)=−111 + (-12) = -11
    −1,12-1, 12−1×12=−12-1 \times 12 = -12−1+12=11-1 + 12 = 11
    2,−62, -62×(−6)=−122 \times (-6) = -122+(−6)=−42 + (-6) = -4
    −2,6-2, 6−2×6=−12-2 \times 6 = -12−2+6=4-2 + 6 = 4
    3,−43, -43×(−4)=−123 \times (-4) = -123+(−4)=−13 + (-4) = -1
    −3,4\mathbf{-3, 4}−3×4=−12\mathbf{-3 \times 4 = -12}−3+4=1\mathbf{-3 + 4 = 1}✓

    The two integers, rr and ss, are −3 and 4\boxed{-3 \text{ and } 4}.

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