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Use substitute method: 3x + 4y = 2, x − y = 5

Mathematics

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Answer

x=227,y=−137x = \frac{22}{7}, y = -\frac{13}{7}

Step-by-step solution

4 steps
  1. Express xx in terms of yy from the second equation.

    Given the equations:

    3x+4y=2(1)3x + 4y = 2 \quad (1) x−y=5(2)x - y = 5 \quad (2)

    From equation (2), we can isolate xx:

    x=5+y(3)x = 5 + y \quad (3)
  2. Substitute the expression for xx from equation (3) into equation (1).

    3(5+y)+4y=23(5 + y) + 4y = 2
  3. Solve the equation for yy.

    15+3y+4y=215 + 3y + 4y = 2 15+7y=215 + 7y = 2

    Subtract 15 from both sides:

    7y=2−157y = 2 - 15 7y=−137y = -13

    Divide by 7:

    y=−137y = -\frac{13}{7}
  4. Substitute the value of yy back into equation (3) to find xx.

    x=5+(−137)x = 5 + \left(-\frac{13}{7}\right) x=5−137x = 5 - \frac{13}{7}

    To combine these, find a common denominator:

    x=5×77−137x = \frac{5 \times 7}{7} - \frac{13}{7} x=357−137x = \frac{35}{7} - \frac{13}{7} x=35−137x = \frac{35 - 13}{7} x=227x = \frac{22}{7}

    The solution is:

    x=227,y=−137x = \frac{22}{7}, y = -\frac{13}{7}
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