In the figure below, O is the center of the circle. Find the value of ACB.

Mathematics
In the figure below, O is the center of the circle. Find the value of ACB.

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Answer

\frac{PQ^{2} + QR^{2} - PR^{2}}{2 \cdot PQ \cdot QR}$$

Step 1: Use the cosine rule to find ∠Q\angle Q.

cos⁡Q=PQ2+QR2−PR22⋅PQ⋅QR\cos Q = \frac{PQ^{2} + QR^{2} - PR^{2}}{2 \cdot PQ \cdot QR}

Step 2: Substitute the side lengths PQ=8.3PQ = 8.3 cm, QR=9.2QR = 9.2 cm, PR=7.6PR = 7.6 cm.

PQ2=8.32=68.89 cm2PQ^{2} = 8.3^{2} = 68.89\, cm^{2}

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Exercise 18 Step 1: Use the cosine rule to find Q. Q = PQ^2 + QR^2 - PR^22 · PQ · QR Step 2: Substitute the side lengths PQ = 8.3 cm, QR = 9.2 cm, PR = 7.6 cm.

In the figure below, O is the center of the circle. Find the value of ACB.
Mathematics

This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Exercise 18 Step 1: Use the cosine rule to find Q. Q = PQ^2 + QR^2 - PR^22 · PQ · QR Step 2: Substitute the side lengths PQ = 8.3 cm, QR = 9.2 cm, PR = 7.6 cm. PQ^2 = 8.3^2 = 68.89\, cm^2 QR^2 =