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Using appropriate mathematical reasoning: (a) Determine the distance of the direct route from the second retail outlet back to the warehouse. (b) Advise the transport manager whether the truck will return to the warehouse by 5:30 p.m. Justify your answer using calculations.

Mathematics

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2 parts
a

109.2 km\text{109.2 km}

b

3:19 p.m.\text{3:19 p.m.}

Step-by-step solution

6 steps

Huu hapa ni utatuzi wa swali lako:

Part a· 2 steps

Pata umbali wa moja kwa moja kutoka duka la pili hadi ghala.

  1. Pata pembe kati ya njia za ghala-duka la kwanza na ghala-duka la pili.

    Mwelekeo wa duka la kwanza (R1) kutoka ghala (W) ni N75°W. Hii inamaanisha 75∘75^\circ magharibi mwa kaskazini. Mwelekeo wa duka la pili (R2) kutoka ghala (W) ni 150∘150^\circ (kutoka kaskazini kisaa). Pembe kati ya WR1 na WR2 kwenye ghala (W) ni tofauti ya pembe hizi kutoka kaskazini.

    • Pembe ya WR1 kutoka kaskazini (kisaa) ni 360∘−75∘=285∘360^\circ - 75^\circ = 285^\circ.
    • Pembe ya WR2 kutoka kaskazini (kisaa) ni 150∘150^\circ.
    • Pembe ∠R1WR2=∣285∘−150∘∣=135∘\angle R1WR2 = |285^\circ - 150^\circ| = 135^\circ.
  2. Tumia Kanuni ya Kosine kupata umbali wa moja kwa moja kutoka R2 hadi W.

    Tunayo pembetatu W-R1-R2. Umbali WR1 = 150 km. Umbali R1R2 = Kasi ×\times Muda = 80 km/h×3 h=24080 \text{ km/h} \times 3 \text{ h} = 240 km. Pembe ∠R1WR2=135∘\angle R1WR2 = 135^\circ. Tunatafuta umbali WR2 (tuiite d2d_2).
    Kwa kutumia Kanuni ya Kosine: R1R22=WR12+WR22−2(WR1)(WR2)cos⁡(∠R1WR2)R1R2^2 = WR1^2 + WR2^2 - 2(WR1)(WR2) \cos(\angle R1WR2)

    2402=1502+d22−2(150)(d2)cos⁡(135∘)240^2 = 150^2 + d_2^2 - 2(150)(d_2) \cos(135^\circ) 57600=22500+d22−300d2(−22)57600 = 22500 + d_2^2 - 300 d_2 \left(-\frac{\sqrt{2}}{2}\right) 57600=22500+d22+1502d257600 = 22500 + d_2^2 + 150\sqrt{2} d_2 d22+1502d2−35100=0d_2^2 + 150\sqrt{2} d_2 - 35100 = 0

    Tumia fomula ya quadratic d2=−b±b2−4ac2ad_2 = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}:

    d2=−1502±(1502)2−4(1)(−35100)2d_2 = \frac{-150\sqrt{2} \pm \sqrt{(150\sqrt{2})^2 - 4(1)(-35100)}}{2} d2=−212.132±45000+1404002d_2 = \frac{-212.132 \pm \sqrt{45000 + 140400}}{2} d2=−212.132±1854002d_2 = \frac{-212.132 \pm \sqrt{185400}}{2} d2=−212.132±430.5812d_2 = \frac{-212.132 \pm 430.581}{2}

    Kwa kuwa umbali hauwezi kuwa hasi:

    d2=−212.132+430.5812=218.4492≈109.22 kmd_2 = \frac{-212.132 + 430.581}{2} = \frac{218.449}{2} \approx 109.22 \text{ km}

    Umbali wa moja kwa moja kutoka duka la pili hadi ghala ni 109.2 km\boxed{\text{109.2 km}}.

Part b

3:19 p.m.\text{3:19 p.m.}

Mshauri meneja wa usafiri kama lori litarejea ghala ifikapo saa 5:30 p.m.

  1. Kokotoa muda wa kuondoka kwenye duka la kwanza (R1).

    • Lori liliondoka ghala saa 7:00 a.m.
    • Liliwasili R1 saa 8:45 a.m.
    • Muda wa kupakua na kuangalia hisa R1 = dakika 45.
    • Muda wa kuondoka R1 = 8:45 a.m. + 45 dakika = 9:30 a.m.
  2. Kokotoa muda wa kuondoka kwenye duka la pili (R2).

    • Lori liliondoka R1 saa 9:30 a.m.
    • Muda wa kusafiri kutoka R1 hadi R2 = 3 saa.
    • Muda wa kuwasili R2 = 9:30 a.m. + 3 saa = 12:30 p.m.
    • Muda wa kupakua R2 = 1 saa.
    • Muda wa kuondoka R2 = 12:30 p.m. + 1 saa = 1:30 p.m.
  3. Kokotoa muda wa kusafiri kurudi ghala (W) na muda wa kuwasili.

    • Umbali kutoka R2 hadi W = 109.22 km (kutoka sehemu a).
    • Kasi ya kurudi = 60 km/h.
    • Muda wa kusafiri kurudi W = Umbali / Kasi = 109.22 km/60 km/h≈1.8203109.22 \text{ km} / 60 \text{ km/h} \approx 1.8203 saa.
    • Badilisha kuwa saa na dakika: 1.8203 h=1 h+(0.8203×60) min≈1 h 49 min1.8203 \text{ h} = 1 \text{ h} + (0.8203 \times 60) \text{ min} \approx 1 \text{ h } 49 \text{ min}.
    • Lori liliondoka R2 saa 1:30 p.m.
    • Muda wa kuwasili W = 1:30 p.m. + 1 saa 49 dakika = 3:19 p.m.
  4. Linganisha muda wa kuwasili na muda unaohitajika.

    Muda wa kuwasili ghala ni 3:19 p.m. Muda unaohitajika wa kurudi ni kabla ya 5:30 p.m.
    Kwa kuwa 3:19 p.m. ni kabla ya 5:30 p.m., lori litarejea ghala kwa wakati.

    Lori litarejea ghala kabla ya saa 5:30 p.m. Lori litawasili ghala saa 3:19 p.m.\boxed{\text{3:19 p.m.}}, ambayo ni mapema kuliko muda uliowekwa wa saa 5:30 p.m.

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