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Using mathematical tables, find the reciprocal of 0.5641, hence evaluate sqrt(0.0441)0.5641. In the diagram below, XY is a transverse tangent to the circles whose centres are A and B with radii 20cm a

Mathematics

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1. Using mathematical tables, find the reciprocal of 0.5641, hence evaluate 0.04410.5641\frac{\sqrt{0.0441}}{0.5641}.

  • Step 1: Find the reciprocal of 0.5641. The reciprocal of 0.5641 is 10.5641\frac{1}{0.5641}. Using a calculator (or mathematical tables for reciprocals):

    10.5641≈1.772735\frac{1}{0.5641} \approx 1.772735
  • Step 2: Find the square root of 0.0441. Using a calculator (or mathematical tables for square roots):

    0.0441=0.21\sqrt{0.0441} = 0.21
  • Step 3: Evaluate the expression. Substitute the values found in Step 1 and Step 2 into the expression:

    0.04410.5641=0.210.5641\frac{\sqrt{0.0441}}{0.5641} = \frac{0.21}{0.5641}

    This can also be written as 0.21×10.56410.21 \times \frac{1}{0.5641}.

    0.21×1.772735≈0.3722740.21 \times 1.772735 \approx 0.372274

    Rounding to four decimal places:

    0.210.5641≈0.3723\frac{0.21}{0.5641} \approx 0.3723

    The final answer is 0.3723\boxed{0.3723}

2. In the diagram below, XY is a transverse tangent to the circles whose centres are A and B with radii 20cm and 12cm respectively. The distance between centres A and B is 40cm. Calculate the length of tangent XY.

  • Step 1: Identify the given values. Radius of circle A, R1=20R_1 = 20 cm. Radius of circle B, R2=12R_2 = 12 cm. Distance between centres A and B, D=40D = 40 cm. We need to find the length of the transverse common tangent, L=XYL = XY.

  • Step 2: Use the formula for the length of a transverse common tangent. The formula for the length of a transverse common tangent is:

    L=D2−(R1+R2)2L = \sqrt{D^2 - (R_1 + R_2)^2}
  • Step 3: Substitute the values and calculate.

    L=402−(20+12)2L = \sqrt{40^2 - (20 + 12)^2} L=402−322L = \sqrt{40^2 - 32^2} L=1600−1024L = \sqrt{1600 - 1024} L=576L = \sqrt{576} L=24 cmL = 24 \text{ cm}

    The final answer is 24 cm\boxed{24 \text{ cm}}

3. The figure below shows a right pyramid on a square base of side 10cm. The slant length of the pyramid is 13cm. X is the mid-point of RS and OY is the perpendicular height of the pyramid. Calculate the height of the pyramid.

  • Step 1: Identify the given information from the figure and text. The base PQRS is a square with side length = 10 cm. The slant edge YS = 13 cm (as indicated in the diagram). OY is the perpendicular height of the pyramid. O is the center of the square base.

  • Step 2: Calculate the length of OS. O is the center of the square base. OS is half the length

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