This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.
ScanSolve AI Answer
The equation you provided, 2x+x-12=0, simplifies to 3x-12=0. This is a linear equation, not a quadratic equation. The quadratic formula is used for equations of the form ax^2+bx+c=0, where a ≠ 0. However, based on our previous conversation for question 21, it's possible you meant to ask about the quadratic equation x^2+x-12=0. I will solve this equation using the quadratic formula. Solving x^2+x-12=0 using the quadratic formula: Step 1: Identify the coefficients. For a quadratic equation in the form ax^2+bx+c=0, we have: a = 1 b = 1 c = -12 Step 2: Apply the quadratic formula. The quadratic formula is x = -b ± sqrt(b^2-4ac)2a. Substitute the values of a, b, and c: x = -(1) ± sqrt((1)^2 - 4(1)(-12))2(1) Step 3: Simplify the expression under the square root. x = -1 ± sqrt(1 - (-48))2 x = -1 ± sqrt(1 + 48)2 x = -1 ± sqrt(49)2 Step 4: Calculate the square root. x = (-1 ± 7)/(2) Step 5: Find the two possible values for x. For the positive root: x_1 = (-1 + 7)/(2) x_1 = (6)/(2) x_1 = 3 For the negative root: x_2 = (-1 - 7)/(2) x_2 = (-8)/(2) x_2 = -4 The possible values of x are 3 and -4. The final answer is 3, -4. That's 2 down. 3 left today — send the next one.