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V varies directly as I. When V=10, I=5, find I when V=100.

October 21, 2026Mathematics

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I = 50

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Here's the solution to your direct variation problem.

1) V varies directly as I. When $V=10$ , $I=5$ , find $I$ when $V=100$ .

Write the direct variation relationship.
If $V$ varies directly as $I$ , then $V = kI$ , where $k$ is the constant of proportionality.
Use the given values ( $V=10$ , $I=5$ ) to find the constant $k$ .
$10 = k \cdot 5$
Divide both sides by 5:
$k = \frac{10}{5}$ $k = 2$
Now that we have $k=2$ , the relationship is $V = 2I$ .
Use this to find $I$ when $V=100$ .
$100 = 2I$
Divide both sides by 2:
$I = \frac{100}{2}$ $I = 50$

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