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Calculate the value of 32)/(185.4) using logarithms.

Mathematics

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Step-by-step solution

3 steps
  1. Let the given expression be YY.

    Y=36.72×(0.46)2185.43Y = \sqrt[3]{\frac{36.72 \times (0.46)^2}{185.4}}

    Rewrite the cube root as an exponent:

    Y=(36.72×(0.46)2185.4)13Y = \left(\frac{36.72 \times (0.46)^2}{185.4}\right)^{\frac{1}{3}}
  2. Take the logarithm (base 10) of both sides.

    log⁡Y=log⁡((36.72×(0.46)2185.4)13)\log Y = \log \left(\left(\frac{36.72 \times (0.46)^2}{185.4}\right)^{\frac{1}{3}}\right)

    Apply the logarithm rule log⁡(AB)=Blog⁡A\log(A^B) = B \log A:

    log⁡Y=13log⁡(36.72×(0.46)2185.4)\log Y = \frac{1}{3} \log \left(\frac{36.72 \times (0.46)^2}{185.4}\right)

    Apply the logarithm rules log⁡(AB)=log⁡A−log⁡B\log\left(\frac{A}{B}\right) = \log A - \log B and log⁡(AB)=log⁡A+log⁡B\log(AB) = \log A + \log B:

    log⁡Y=13(log⁡(36.72)+log⁡((0.46)2)−log⁡(185.4))\log Y = \frac{1}{3} \left( \log(36.72) + \log((0.46)^2) - \log(185.4) \right)

    Apply the logarithm rule log⁡(AB)=Blog⁡A\log(A^B) = B \log A again:

    log⁡Y=13(log⁡(36.72)+2log⁡(0.46)−log⁡(185.4))\log Y = \frac{1}{3} \left( \log(36.72) + 2 \log(0.46) - \log(185.4) \right)
  3. Find the logarithms of each number using logarithm tables.

    • For log⁡(36.72)\log(36.72): Characteristic: 1 (since 36.72 has two digits before the decimal point, 2−1=12-1=1). Mantissa: Look up 36 under 7 (which is 0.5647) and mean difference for 2 (which is 2). So, log⁡(36.72)=1.5647+0.0002=1.5649\log(36.72) = 1.5647 + 0.0002 = 1.5649.

    • For log⁡(0.46)\log(0.46): Characteristic: 1ˉ\bar{1} (since the first significant digit is in the first decimal place). Mantissa: Look up 46 under 0 (which is 0.6628). So, log⁡(0.46)=1ˉ.6628\log(0.46) = \bar{1}.6628.

    • For log⁡(185.4)\log(185.4): Characteristic: 2 (since 185.4 has three digits before the decimal point, 3−1=23-1=2). Mantissa: Look up $

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