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Determine the value of the lowercase letters and provide reasons.

Mathematics

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Here are the solutions for , determining the value of the lowercase letters and providing reasons.

Figure 1:
Given OO is the center of the circle.
The angle 32∘32^\circ is ∠OJN\angle OJN.

Step 1: Find ∠JON\angle JON.
In △OJN\triangle OJN, OJ=ONOJ = ON (radii). Therefore, △OJN\triangle OJN is an isosceles triangle.

∠ONJ=∠OJN=32∘\angle ONJ = \angle OJN = 32^\circ

The sum of angles in △OJN\triangle OJN is 180∘180^\circ.

∠JON=180∘−(∠OJN+∠ONJ)\angle JON = 180^\circ - (\angle OJN + \angle ONJ)
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