This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

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Answer
k = 4
a) The values of and
Step 1: Use the fact that line passes through the point to find . The equation of line is . Substitute and into the equation:
Step 2: Find the gradient of line . Rearrange the equation into the form : The gradient of is .
Step 3: Find the gradient of line . The equation of line is . Rearrange this into the form : The gradient of is .
Step 4: Use the condition that is perpendicular to to find . For perpendicular lines, the product of their gradients is : .
b) The equation of a line which is parallel to in the form where a, b and c are constants.
Step 1: Find the gradient of line using the value of . The gradient of is . Substitute : Since line is parallel to , their gradients are equal. So, .
Step 2: Write the equation of in the form . The equation of can be written as , where is an arbitrary constant. To convert this to the form , multiply by 3: Rearrange the terms: Let . Since is an arbitrary constant, is also an arbitrary constant.
c) The obtuse angle with which line makes with x-axis.
Step 1: Use the gradient of to find the acute angle it makes with the x-axis. The gradient of is . Let be the acute angle the line makes with the x-axis.
Step 2: Calculate the obtuse angle. The obtuse angle is .
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a) The values of k and p Step 1: Use the fact that line L_1 passes through the point (-3, -1) to find k.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.