Find the values of x and y given the diagram with angles labeled x, 92 degrees, 41 degrees and y.

The angle $x$ and the $92^\circ$ angle form a linear pair on a straight line. Angles on a straight line sum to $180^\circ$.

$$x + 92^\circ = 180^\circ$$

Subtract $92^\circ$ from both sides:

$$x = 180^\circ - 92^\circ$$ $$x = 88^\circ$$

The value of $x$ is \boxed{\text{88^\circ}}.

The sum of the interior angles in a triangle is $180^\circ$. The interior angles are $y$, $41^\circ$, and $92^\circ$.

$$y + 41^\circ + 92^\circ = 180^\circ$$ $$y + 133^\circ = 180^\circ$$

Subtract $133^\circ$ from both sides:

$$y = 180^\circ - 133^\circ$$ $$y = 47^\circ$$

The value of $y$ is \boxed{\text{47^\circ}}.