Calculate the volume of cement needed to cast a triangle shaped concrete slab. The dimensions and shape are given in the drawing below.

The drawing shows a right-angled triangle with two sides measuring $600 \text{ cm}$ each, forming the right angle. These sides serve as the base and height of the triangle.
The formula for the area of a triangle is:

$$\text{Area} = \frac{1}{2} \times \text{base} \times \text{height}$$

Substitute the given dimensions:

$$\text{Area} = \frac{1}{2} \times 600 \text{ cm} \times 600 \text{ cm}$$ $$\text{Area} = \frac{1}{2} \times 360000 \text{ cm}^2$$ $$\text{Area} = 180000 \text{ cm}^2$$

The thickness of the slab is given as $10 \text{ cm}$. The volume of a prism (like this slab) is the area of its base multiplied by its thickness.

$$\text{Volume} = \text{Area of base} \times \text{thickness}$$ $$\text{Volume} = 180000 \text{ cm}^2 \times 10 \text{ cm}$$ $$\text{Volume} = 1800000 \text{ cm}^3$$

We know that $1 \text{ m} = 100 \text{ cm}$, so $1 \text{ m}^3 = (100 \text{ cm})^3 = 1,000,000 \text{ cm}^3$.

$$\text{Volume in m}^3 = \frac{1800000 \text{ cm}^3}{1000000 \text{ cm}^3/\text{m}^3}$$ $$\text{Volume in m}^3 = 1.8 \text{ m}^3$$

The volume of cement needed is $\boxed{1.8 \text{ m}^3}$ or $\boxed{1800000 \text{ cm}^3}$.