Calculate the volume of cuboids given different sets of dimensions or volume.

    $$
    V = 6 \text{ m} \times 5 \text{ m} \times 2 \text{ m}
    $$
    $$
    V = 60 \text{ m}^3
    $$
*   Missing value: $\boxed{60 \text{ m}^3}$

    $$
    \text{Height} = \frac{\text{Volume}}{\text{Length} \times \text{Width}}
    $$

    $$
    \text{Height} = \frac{270 \text{ m}^3}{7 \text{ m} \times 6 \text{ m}}
    $$
    $$
    \text{Height} = \frac{270 \text{ m}^3}{42 \text{ m}^2}
    $$
    $$
    \text{Height} = \frac{45}{7} \text{ m} \approx 6.43 \text{ m}
    $$
*   Missing value: $\boxed{\frac{45}{7} \text{ m}}$ or $\boxed{6.43 \text{ m}}$ (approximately)

    $$
    \text{Length} = \frac{\text{Volume}}{\text{Width} \times \text{Height}}
    $$

    $$
    \text{Length} = \frac{85000 \text{ cm}^3}{50 \text{ cm} \times 80 \text{ cm}}
    $$
    $$
    \text{Length} = \frac{85000 \text{ cm}^3}{4000 \text{ cm}^2}
    $$
    $$
    \text{Length} = \frac{85}{4} \text{ cm} = 21.25 \text{ cm}
    $$
*   Missing value: $\boxed{21.25 \text{ cm}}$

    $$
    V = 70 \text{ cm} \times 50 \text{ cm} \times 80 \text{ cm}
    $$
    $$
    V = 280000 \text{ cm}^3
    $$
*   Missing value: $\boxed{280000 \text{ cm}^3}$