Calculate the volume of a cone with radius 3.5 cm and height 10 cm, a cube with side 5 cm, and a cuboid with length 8 cm, width 4 cm, and height 2 cm.

Given $r = 3.5 \text{ cm}$ and $h = 10 \text{ cm}$. Use $\pi = \frac{22}{7}$.

$$V = \frac{1}{3} \times \frac{22}{7} \times (3.5 \text{ cm})^2 \times 10 \text{ cm}$$ $$V = \frac{1}{3} \times \frac{22}{7} \times (3.5 \times 3.5) \text{ cm}^2 \times 10 \text{ cm}$$ $$V = \frac{1}{3} \times \frac{22}{7} \times 12.25 \text{ cm}^2 \times 10 \text{ cm}$$ $$V = \frac{1}{3} \times 22 \times 1.75 \text{ cm}^2 \times 10 \text{ cm}$$ $$V = \frac{1}{3} \times 38.5 \text{ cm}^2 \times 10 \text{ cm}$$ $$V = \frac{385}{3} \text{ cm}^3$$ $$V \approx \boxed{\text{128.33 cm}^3}$$

Given side $s = 5 \text{ cm}$.

$$V = (5 \text{ cm})^3$$ $$V = 5 \times 5 \times 5 \text{ cm}^3$$ $$V = \boxed{\text{125 cm}^3}$$

Given length $l = 8 \text{ cm}$, width $w = 4 \text{ cm}$, and height $h = 2 \text{ cm}$.

$$V = 8 \text{ cm} \times 4 \text{ cm} \times 2 \text{ cm}$$ $$V = 32 \text{ cm}^2 \times 2 \text{ cm}$$ $$V = \boxed{\text{64 cm}^3}$$

Given $r = 7 \text{ cm}$ and $h = 10 \text{ cm}$. Use $\pi = \frac{22}{7}$.

$$V = \frac{22}{7} \times (7 \text{ cm})^2 \times 10 \text{ cm}$$ $$V = \frac{22}{7} \times 49 \text{ cm}^2 \times 10 \text{ cm}$$ $$V = 22 \times 7 \text{ cm}^2 \times 10 \text{ cm}$$ $$V = 154 \text{ cm}^2 \times 10 \text{ cm}$$ $$V = \boxed{\text{1540 cm}^3}$$

: A rectangular tank measures $6 \text{ metres} \times 5 \text{ metres} \times 4 \text{ metres}$. How many litres of water can it hold?

$$V = lwh$$ $$V = 6 \text{ m} \times 5 \text{ m} \times 4 \text{ m}$$ $$V = 30 \text{ m}^2 \times 4 \text{ m}$$ $$V = 120 \text{ m}^3$$

We know that $1 \text{ m}^3 = 1000 \text{ litres}$.

$$V_{litres} = 120 \text{ m}^3 \times \frac{1000 \text{ litres}}{1 \text{ m}^3}$$ $$V_{litres} = \boxed{\text{120000 litres}}$$

: Find the surface area of a sphere of radius $7 \text{ cm}$.

Given $r = 7 \text{ cm}$. Use $\pi = \frac{22}{7}$.

$$A = 4 \times \frac{22}{7} \times (7 \text{ cm})^2$$ $$A = 4 \times \frac{22}{7} \times 49 \text{ cm}^2$$ $$A = 4 \times 22 \times 7 \text{ cm}^2$$ $$A = 88 \times 7 \text{ cm}^2$$ $$A = \boxed{\text{616 cm}^2}$$

: Find the surface area of a cuboid $8 \text{ cm} \times 6 \text{ cm} \times 4 \text{ cm}$.

Given length $l = 8 \text{ cm}$, width $w = 6 \text{ cm}$, and height $h = 4 \text{ cm}$.

$$A = 2((8 \text{ cm} \times 6 \text{ cm}) + (8 \text{ cm} \times 4 \text{ cm}) + (6 \text{ cm} \times 4 \text{ cm}))$$ $$A = 2(48 \text{ cm}^2 + 32 \text{ cm}^2 + 24 \text{ cm}^2)$$ $$A = 2(104 \text{ cm}^2)$$ $$A = \boxed{\text{208 cm}^2}$$

: A hemisphere bowl of radius $14 \text{ cm}$ is to be painted.

Assuming the bowl is open, only the curved surface area needs to be painted.

Given $r = 14 \text{ cm}$. Use $\pi = \frac{22}{7}$.

$$A = 2 \times \frac{22}{7} \times (14 \text{ cm})^2$$ $$A = 2 \times \frac{22}{7} \times 196 \text{ cm}^2$$ $$A = 2 \times 22 \times 28 \text{ cm}^2$$ $$A = 44 \times 28 \text{ cm}^2$$ $$A = \boxed{\text{1232 cm}^2}$$