A rectangular water tank is 90 cm wide and 40 cm deep. If it can contain 576 litres of water, what is its length?

The dimensions are:
Length ($l$) = 22 cm
Breadth ($b$) = 12 cm
Height ($h$) = 7.5 cm

The formula for the volume of a cuboid is $V = l \times b \times h$.

$$V = 22 \text{ cm} \times 12 \text{ cm} \times 7.5 \text{ cm}$$ $$V = 264 \text{ cm}^2 \times 7.5 \text{ cm}$$ $$V = 1980 \text{ cm}^3$$

The formula for the lateral surface area of a cuboid is $\text{LSA} = 2h(l+b)$.

$$\text{LSA} = 2 \times 7.5 \text{ cm} \times (22 \text{ cm} + 12 \text{ cm})$$ $$\text{LSA} = 15 \text{ cm} \times (34 \text{ cm})$$ $$\text{LSA} = 510 \text{ cm}^2$$

The formula for the total surface area of a cuboid is $\text{TSA} = 2(lb + bh + hl)$.

$$\text{TSA} = 2((22 \text{ cm} \times 12 \text{ cm}) + (12 \text{ cm} \times 7.5 \text{ cm}) + (7.5 \text{ cm} \times 22 \text{ cm}))$$ $$\text{TSA} = 2(264 \text{ cm}^2 + 90 \text{ cm}^2 + 165 \text{ cm}^2)$$ $$\text{TSA} = 2(519 \text{ cm}^2)$$ $$\text{TSA} = 1038 \text{ cm}^2$$

The volume, lateral surface area, and total surface area for the given dimensions are:
Volume: $\boxed{\text{1980 cm}^3}$
Lateral Surface Area: $\boxed{\text{510 cm}^2}$
Total Surface Area: $\boxed{\text{1038 cm}^2}$