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Work out: 3^(4n) * 3^(-2n) / 3ⁿ = 32

Mathematics

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Answer

n=2n = \mathbf{2}

Step-by-step solution

3 steps

Ili kutatua tatizo hili, tutatumia sheria za vipeo (exponents).

  1. Rahisisha namba (numerator) ya usemi kwa kutumia sheria ya vipeo am×an=am+na^m \times a^n = a^{m+n}.

    34n×3−2n=34n+(−2n)=34n−2n=32n3^{4n} \times 3^{-2n} = 3^{4n + (-2n)} = 3^{4n - 2n} = 3^{2n}
  2. Sasa usemi umekuwa 32n3n\frac{3^{2n}}{3^n}.

    Rahisisha usemi huu kwa kutumia sheria ya vipeo aman=am−n\frac{a^m}{a^n} = a^{m-n}.

    32n3n=32n−n=3n\frac{3^{2n}}{3^n} = 3^{2n - n} = 3^n
  3. Linganisha matokeo na upande wa kulia wa mlinganyo, ambao ni 323^2.

    3n=323^n = 3^2

    Kwa kuwa besi (base) ni sawa (3), vipeo (exponents) lazima viwe sawa.

    n=2n = 2
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