Work out: 340 × 3⁻²⁰ / 35

Ili kutatua tatizo hili, tutatumia sheria za vipeo (exponents). Step 1: Rahisisha sehemu ya kwanza ya usemi, ambayo ni (3¹⁰)/(3⁸). Tunatumia sheria ya vipeo inayosema kwamba (a^m)/(aⁿ) = a^(m−n). (3¹⁰)/(3⁸) = 3¹⁰⁻⁸ = 3² Step 2: Sasa zidisha matokeo ya Step 1 na 3⁻²⁰. Tunatumia sheria ya vipeo inayosema kwamba a^m × aⁿ = a^(m+n). 3² × 3⁻²⁰ = 3²⁺⁽⁻²⁰⁾ = 3²⁻²⁰ = 3⁻¹⁸ Jibu la mwisho ni: 3⁻¹⁸

Work out: 340 × 3⁻²⁰ / 35

Ili kutatua tatizo hili, tutatumia sheria za vipeo (exponents). Step 1: Rahisisha sehemu ya kwanza ya usemi, ambayo ni (3¹⁰)/(3⁸). Tunatumia sheria ya vipeo inayosema kwamba (a^m)/(aⁿ) = a^(m−n). (3¹⁰)/(3⁸) = 3¹⁰⁻⁸ = 3² Step 2: Sasa zidisha matokeo ya Step 1 na 3⁻²⁰. Tunatumia sheria ya vipeo inayosema kwamba a^m × aⁿ = a^(m+n). 3² × 3⁻²⁰ = 3²⁺⁽⁻²⁰⁾ = 3²⁻²⁰ = 3⁻¹⁸ Jibu la mwisho ni: 3⁻¹⁸

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Work out: 340 x 3⁻²⁰ / 35

July 28, 2026Mathematics

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Answer

3^{-18}

Step-by-step solution

2 steps

Ili kutatua tatizo hili, tutatumia sheria za vipeo (exponents).

Rahisisha sehemu ya kwanza ya usemi, ambayo ni $\frac{3^{10}}{3^8}$ .
Tunatumia sheria ya vipeo inayosema kwamba $\frac{a^m}{a^n} = a^{m-n}$ .
$\frac{3^{10}}{3^8} = 3^{10-8} = 3^2$
Sasa zidisha matokeo ya Step 1 na $3^{-20}$ .
Tunatumia sheria ya vipeo inayosema kwamba $a^m \times a^n = a^{m+n}$ .
$3^2 \times 3^{-20} = 3^{2 + (-20)} = 3^{2-20} = 3^{-18}$
Jibu la mwisho ni:
$3^{-18}$

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Work out: 340 x 3⁻²⁰ / 35

Answer

Step-by-step solution

Rahisisha sehemu ya kwanza ya usemi, ambayo ni 31038\frac{3^{10}}{3^8}38310​.

Sasa zidisha matokeo ya Step 1 na 3−203^{-20}3−20.

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Rahisisha sehemu ya kwanza ya usemi, ambayo ni $\frac{3^{10}}{3^8}$ .

Sasa zidisha matokeo ya Step 1 na $3^{-20}$ .