This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.

ScanSolve AI Answer
Answer
32 km/h
Okay master, let's solve these problems.
Problem (b): Work out the average speed of the bus for the whole journey.
Step 1: Identify the total distance and total time from the student's work. The total distance (T.D.C) is given as km. The total time (T.T.T) is given as hours.
Step 2: Calculate the total time.
Step 3: Calculate the average speed using the formula . The average speed of the bus for the whole journey is .
: The median of four consecutive counting numbers is . Find the numbers.
Step 1: Represent the four consecutive counting numbers. Let the four consecutive counting numbers be .
Step 2: Set up the equation for the median. For an even set of numbers, the median is the average of the two middle numbers. In this case, the middle numbers are and . The median is . We are given that the median is , which can be written as .
Step 3: Solve the equation for . Multiply both sides by 2: Subtract 3 from both sides: Divide by 2:
Step 4: Find the four consecutive numbers. Substitute into our representations: • First number: • Second number: • Third number: • Fourth number: The four consecutive counting numbers are .
Last free one today — make it count tomorrow, or type /upgrade for unlimited.
Get instant step-by-step solutions to any question. Free to start.
Ask Your Question
Handwritten Step-by-Step Solution
Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.
Try on WhatsAppStill have questions?
Okay master, let's solve these problems. Problem (b): Work out the average speed of the bus for the whole journey.
This mathematics problem involves applying core mathematical principles and formulas. Below you will find a complete step-by-step solution with detailed explanations for each step, helping you understand not just the answer but the method behind it.