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Work out the average speed of the bus for the whole journey. The median of four consecutive counting numbers is 8½. Find the numbers.

Mathematics

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Answer

32 km/h\text{32 km/h}

7, 8, 9, 10

Step-by-step solution

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Problem (b): Work out the average speed of the bus for the whole journey.

  1. Identify the total distance and total time from the student's work.

    The total distance (T.D.C) is given as 480 km.
    The total time (T.T.T) is given as (6+8+1)(6+8+1) hours.

  2. Calculate the total time.

    Total time=6+8+1=15 hours\text{Total time} = 6 + 8 + 1 = 15 \text{ hours}
  3. Calculate the average speed using the formula Speed=DistanceTime\text{Speed} = \frac{\text{Distance}}{\text{Time}}.

    Average Speed=480 km15 hours\text{Average Speed} = \frac{480 \text{ km}}{15 \text{ hours}} Average Speed=32 km/h\text{Average Speed} = 32 \text{ km/h}

    The average speed of the bus for the whole journey is 32 km/h\boxed{\text{32 km/h}}.

    : The median of four consecutive counting numbers is 8128\frac{1}{2}. Find the numbers.

  4. Represent the four consecutive counting numbers.

    Let the four consecutive counting numbers be n,n+1,n+2,n+3n, n+1, n+2, n+3.

  5. Set up the equation for the median.

    For an even set of numbers, the median is the average of the two middle numbers. In this case, the middle numbers are n+1n+1 and n+2n+2.
    The median is (n+1)+(n+2)2\frac{(n+1) + (n+2)}{2}.
    We are given that the median is 8128\frac{1}{2}, which can be written as 172\frac{17}{2}.

    (n+1)+(n+2)2=172\frac{(n+1) + (n+2)}{2} = \frac{17}{2}
  6. Solve the equation for nn.

    2n+32=172\frac{2n+3}{2} = \frac{17}{2}

    Multiply both sides by 2:

    2n+3=172n+3 = 17

    Subtract 3 from both sides:

    2n=17−32n = 17 - 3 2n=142n = 14

    Divide by 2:

    n=142n = \frac{14}{2} n=7n = 7
  7. Find the four consecutive numbers.

    Substitute n=7n=7 into our representations:

    • First number: n=7n = 7
    • Second number: n+1=7+1=8n+1 = 7+1 = 8
    • Third number: n+2=7+2=9n+2 = 7+2 = 9
    • Fourth number: n+3=7+3=10n+3 = 7+3 = 10 The four consecutive counting numbers are 7,8,9,10\boxed{7, 8, 9, 10}.
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