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Work out the smallest value of a that is a solution to the equation 4/(2a-1) + (a+7)/(3a−5) = 2. Give your answer to 2 d.p.

Mathematics

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Answer

a=0.88a = 0.88

Step-by-step solution

7 steps

To work out the smallest value of aa that is a solution to the equation 42a−1+a+73a−5=2\frac{4}{2a - 1} + \frac{a + 7}{3a - 5} = 2, we first need to combine the fractions and solve the resulting quadratic equation.

  1. Find a common denominator for the fractions on the left side, which is (2a−1)(3a−5)(2a - 1)(3a - 5).

    4(3a−5)(2a−1)(3a−5)+(a+7)(2a−1)(2a−1)(3a−5)=2\frac{4(3a - 5)}{(2a - 1)(3a - 5)} + \frac{(a + 7)(2a - 1)}{(2a - 1)(3a - 5)} = 2
  2. Combine the numerators.

    4(3a−5)+(a+7)(2a−1)(2a−1)(3a−5)=2\frac{4(3a - 5) + (a + 7)(2a - 1)}{(2a - 1)(3a - 5)} = 2

    Expand the terms in the numerator:

    4(3a−5)=12a−204(3a - 5) = 12a - 20 (a+7)(2a−1)=2a2−a+14a−7=2a2+13a−7(a + 7)(2a - 1) = 2a^2 - a + 14a - 7 = 2a^2 + 13a - 7

    Sum of numerators:

    (12a−20)+(2a2+13a−7)=2a2+25a−27(12a - 20) + (2a^2 + 13a - 7) = 2a^2 + 25a - 27

    Expand the terms in the denominator:

    (2a−1)(3a−5)=6a2−10a−3a+5=6a2−13a+5(2a - 1)(3a - 5) = 6a^2 - 10a - 3a + 5 = 6a^2 - 13a + 5

    The equation becomes:

    2a2+25a−276a2−13a+5=2\frac{2a^2 + 25a - 27}{6a^2 - 13a + 5} = 2
  3. Multiply both sides by the denominator to eliminate the fraction.

    2a2+25a−27=2(6a2−13a+5)2a^2 + 25a - 27 = 2(6a^2 - 13a + 5) 2a2+25a−27=12a2−26a+102a^2 + 25a - 27 = 12a^2 - 26a + 10
  4. Rearrange the equation into the standard quadratic form Ax2+Bx+C=0Ax^2 + Bx + C = 0.

    Subtract 2a22a^2, 25a25a, and −27-27 from both sides:

    0=12a2−2a2−26a−25a+10+270 = 12a^2 - 2a^2 - 26a - 25a + 10 + 27 0=10a2−51a+370 = 10a^2 - 51a + 37
  5. Solve the quadratic equation 10a2−51a+37=010a^2 - 51a + 37 = 0 using the quadratic formula a=−B±B2−4AC2Aa = \frac{-B \pm \sqrt{B^2 - 4AC}}{2A}.

    Here, A=10A = 10, B=−51B = -51, C=37C = 37.

    a=−(−51)±(−51)2−4(10)(37)2(10)a = \frac{-(-51) \pm \sqrt{(-51)^2 - 4(10)(37)}}{2(10)} a=51±2601−148020a = \frac{51 \pm \sqrt{2601 - 1480}}{20} a=51±112120a = \frac{51 \pm \sqrt{1121}}{20}
  6. Calculate the two possible values for aa and round to 2 decimal places.

    First, calculate the square root: 1121≈33.481338\sqrt{1121} \approx 33.481338

    a1=51+33.48133820=84.48133820≈4.2240669a_1 = \frac{51 + 33.481338}{20} = \frac{84.481338}{20} \approx 4.2240669 a2=51−33.48133820=17.51866220≈0.8759331a_2 = \frac{51 - 33.481338}{20} = \frac{17.518662}{20} \approx 0.8759331
  7. Identify the smallest value and round it to 2 decimal places.

    Comparing a1≈4.22a_1 \approx 4.22 and a2≈0.88a_2 \approx 0.88, the smallest value is 0.8759331.
    Rounding to 2 decimal places, this is 0.88.

    a=0.88a = 0.88
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