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(x-8)(x+8) 4x2 - 25 x3 + 10x + 125

Mathematics

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5 steps

Sawa, Mbari. Haya hapa maswali mawili ya kuweka katika vigawo.

Part a· 2 steps

Weka 4x2−254x^2 - 25 katika vigawo.

  1. Tambua kuwa huu ni tofauti ya miraba miwili (a2−b2a^2 - b^2).

    Hapa, a2=4x2  ⟹  a=2xa^2 = 4x^2 \implies a = 2x.
    Na b2=25  ⟹  b=5b^2 = 25 \implies b = 5.

  2. Tumia fomula ya tofauti ya miraba miwili

    a2−b2=(a−b)(a+b)a^2 - b^2 = (a-b)(a+b).

    4x2−25=(2x−5)(2x+5)4x^2 - 25 = (2x-5)(2x+5)

    Jibu: (2x−5)(2x+5)\boxed{(2x-5)(2x+5)}

Part b· 3 steps

Weka x3+10x+125x^3 + 10x + 125 katika vigawo.

  1. Tambua aina ya usemi.

    Huu ni usemi wa ujazo (cubic polynomial).

  2. Jaribu kutafuta mizizi halisi.

    Kwa usemi P(x)=x3+10x+125P(x) = x^3 + 10x + 125, hakuna mizizi rahisi ya kimantiki (rational roots) inayoweza kupatikana kwa urahisi.

  3. Hitimisho.

    Kwa kuwa usemi huu hauna mizizi rahisi ya kimantiki na derivative yake (3x2+103x^2 + 10) daima ni chanya, inamaanisha kuwa usemi huu hauwezi kuwekwa katika vigawo rahisi vya mstari (linear factors) kwa kutumia namba halisi.

    Jibu: Usemi x3+10x+125 hauwezi kuwekwa katika vigawo rahisi vya mstari kwa kutumia namba halisi.\boxed{\text{Usemi } x^3 + 10x + 125 \text{ hauwezi kuwekwa katika vigawo rahisi vya mstari kwa kutumia namba halisi.}}

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