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Solve x for if 2x6 = 23y + 1

Mathematics

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Answer

x=2y2x = 2^{\frac{y}{2}}

Step-by-step solution

2 steps

Huu hapa utatuzi wa swali lako:

  1. Gawanya pande zote mbili za mlinganyo kwa 2.

    2x6=23y+12x^6 = 2^{3y+1} 2x62=23y+12\frac{2x^6}{2} = \frac{2^{3y+1}}{2} x6=23y+1−1x^6 = 2^{3y+1-1} x6=23yx^6 = 2^{3y}

  2. Chukua mzizi wa sita (sixth root) pande zote mbili ili kupata xx.

    x=(23y)16x = (2^{3y})^{\frac{1}{6}} x=23y6x = 2^{\frac{3y}{6}} x=2y2x = 2^{\frac{y}{2}}
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