Determine the x-intercepts of the quadratic equation: 2x2 − 5x + 3 = 0. Determine the domain of the function: f(x) = sqrt(x+6) − 2.

For $2x^2 - 5x + 3 = 0$, we have $a=2$, $b=-5$, and $c=3$.

The quadratic formula is $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$.

This gives two possible values for $x$:

The $x$-intercepts are where $y=0$, so the points are $(\frac{3}{2}, 0)$ and $(1, 0)$.

The $x$-intercepts are $\boxed{x = \frac{3}{2} \text{ or } x = 1}$.

In this function, the expression under the square root is $x+6$.

The domain is all real numbers greater than or equal to $-6$.

The domain is $\boxed{[-6, \infty)}$.