Yeh question solve plz

$$\frac{2}{5} = \frac{2 \times 2}{5 \times 2} = \frac{4}{10} = \frac{2 \times 3}{5 \times 3} = \frac{6}{15} = \frac{2 \times 5}{5 \times 5} = \frac{10}{25} = \frac{2 \times 7}{5 \times 7} = \frac{14}{35}$$

अतः, $\frac{2}{5}$ के चार समतुल्य भिन्न हैं: $\boxed{\frac{4}{10}, \frac{6}{15}, \frac{10}{25}, \frac{14}{35}}$

$$\frac{3}{5} = \frac{3 \times 2}{5 \times 2} = \frac{6}{10} = \frac{3 \times 3}{5 \times 3} = \frac{9}{15} = \frac{3 \times 5}{5 \times 5} = \frac{15}{25} = \frac{3 \times 7}{5 \times 7} = \frac{21}{35}$$

अतः, $\frac{3}{5}$ के चार समतुल्य भिन्न हैं: $\boxed{\frac{6}{10}, \frac{9}{15}, \frac{15}{25}, \frac{21}{35}}$

$$\frac{2}{7} = \frac{2 \times 2}{7 \times 2} = \frac{4}{14} = \frac{2 \times 3}{7 \times 3} = \frac{6}{21} = \frac{2 \times 5}{7 \times 5} = \frac{10}{35} = \frac{2 \times 7}{7 \times 7} = \frac{14}{49}$$

अतः, $\frac{2}{7}$ के चार समतुल्य भिन्न हैं: $\boxed{\frac{4}{14}, \frac{6}{21}, \frac{10}{35}, \frac{14}{49}}$

$$\frac{3}{7} = \frac{3 \times 2}{7 \times 2} = \frac{6}{14} = \frac{3 \times 3}{7 \times 3} = \frac{9}{21} = \frac{3 \times 5}{7 \times 5} = \frac{15}{35} = \frac{3 \times 7}{7 \times 7} = \frac{21}{49}$$

अतः, $\frac{3}{7}$ के चार समतुल्य भिन्न हैं: $\boxed{\frac{6}{14}, \frac{9}{21}, \frac{15}{35}, \frac{21}{49}}$