We read your photo as:

How do you linearize the exponential equation y = ab^x?

Mathematics

ScanSolve AI Answer

Answer

ln⁡(y)=(ln⁡(b))x+ln⁡(a)\ln(y) = (\ln(b))x + \ln(a)

Step-by-step solution

5 steps

To linearize the equation y=abxy = ab^x, we take the natural logarithm of both sides.

  1. Start with the given equation.

    y=abxy = ab^x
  2. Take the natural logarithm (ln⁡\ln) of both sides.

    ln⁡(y)=ln⁡(abx)\ln(y) = \ln(ab^x)
  3. Use the logarithm property ln⁡(MN)=ln⁡(M)+ln⁡(N)\ln(MN) = \ln(M) + \ln(N) to separate the terms on the right side.

    ln⁡(y)=ln⁡(a)+ln⁡(bx)\ln(y) = \ln(a) + \ln(b^x)
  4. Use the logarithm property ln⁡(MP)=Pln⁡(M)\ln(M^P) = P \ln(M) to bring the exponent xx down.

    ln⁡(y)=ln⁡(a)+xln⁡(b)\ln(y) = \ln(a) + x \ln(b)
  5. Rearrange the equation into the standard linear form Y=mX+cY = mX + c.

    ln⁡(y)=(ln⁡(b))x+ln⁡(a)\ln(y) = (\ln(b))x + \ln(a)

    Here, Y=ln⁡(y)Y = \ln(y), X=xX = x, the slope m=ln⁡(b)m = \ln(b), and the y-intercept c=ln⁡(a)c = \ln(a).

Was this helpful?

Try one yourself

A new problem that tests the same skill.

Still stuck on this one?

Ask a follow-up, and the answer starts from this question.

Got a different question?Ask your own question