A capacitor of 5 microfarads is connected to an A.C source of frequency 50Hz. The capacitive reactance is:

Step 1: Convert the capacitance from microfarads to farads. C = 5 μF = 5 × 10⁻⁶ F Step 2: Use the formula for capacitive reactance. X_C = (1)/(2 π f C) Step 3: Substitute the given values into the formula. X_C = 12 π (50 Hz) (5 × 10⁻⁶ F); X_C = (1)/(2 π (250 × 10⁻⁶)); X_C = 1/0.001570796 X_C ≈ 636.62 Ω The capacitive reactance is approximately 636.62 Ω. 636.62 Ω

A capacitor of 5 microfarads is connected to an A.C source of frequency 50Hz. The capacitive reactance is:

Step 1: Convert the capacitance from microfarads to farads. C = 5 μF = 5 × 10⁻⁶ F Step 2: Use the formula for capacitive reactance. X_C = (1)/(2 π f C) Step 3: Substitute the given values into the formula. X_C = 12 π (50 Hz) (5 × 10⁻⁶ F); X_C = (1)/(2 π (250 × 10⁻⁶)); X_C = 1/0.001570796 X_C ≈ 636.62 Ω The capacitive reactance is approximately 636.62 Ω. 636.62 Ω

Solved: A capacitor of 5 microfarads is connected to an A.C…

X_C = \frac{1}{2 \pi (50 \text{ Hz}) (5 \times 10^{-6} \text{ F})}

X_C = \frac{1}{2 \pi (250 \times 10^{-6})}

X_C = \frac{1}{0.001570796}

X_C \approx 636.62 \text{ } \Omega

The capacitive reactance is approximately 636.62 $\Omega$ .

636.62 \text{ } \Omega

A capacitor of 5 microfarads is connected to an A.C source of frequency 50Hz. The capacitive reactance is:

Answer

Step-by-step solution

Convert the capacitance from microfarads to farads.

Use the formula for capacitive reactance.

Substitute the given values into the formula.

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