A car is being cut open by emergency services. What is the purpose of the tools being used and what principles of physics are involved in their operation?

Step 1: Identify the principle.
The Jaws of Life tool operates on Pascal's principle for hydraulic systems:
$P = \frac{F_1}{A_1} = \frac{F_2}{A_2}$
where $P$ is pressure in Pa (N/m²), $F_1 = 200\ \mathrm{N}$ is input force, $A_1$ is input piston area, $A_2$ is output piston area, and $F_2$ is output force in N.

Step 2: Calculate input piston area.
Input diameter = 2 cm = 0.02 m, so radius $r_1 = 0.01\ \mathrm{m}$.
$A_1 = \pi r_1^2$
$A_1 = \pi (0.01)^2 = \pi \times 0.0001 = 3.14 \times 10^{-4}\ \mathrm{m^2}$

Step 3: Calculate output piston area.
Output diameter = 20 cm = 0.20 m, so radius $r_2 = 0.10\ \mathrm{m}$.
$A_2 = \pi r_2^2$
$A_2 = \pi (0.10)^2 = \pi \times 0.01 = 3.14 \times 10^{-2}\ \mathrm{m^2}$

Step 4: Find area ratio.
$\frac{A_2}{A_1} = \frac{\pi (0.10)^2}{\pi (0.01)^2} = \frac{0.01}{0.0001} = 100$

Step 5: Calculate output force.
$F_2 = F_1 \times \frac{A_2}{A_1}$
$F_2 = 200\ N \times 100 = 20000\ \mathrm{N}$

The output piston exerts $\boxed{20000\ N}$ on the car door.