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A car is being cut open by emergency services. What is the purpose of the tools being used and what principles of physics are involved in their operation?

Physics

ScanSolve AI Answer

Answer

20000 N20000\ \mathrm{N}

Step-by-step solution

5 steps
  1. Identify the principle.

    The Jaws of Life tool operates on Pascal's principle for hydraulic systems:

    P=F1A1=F2A2P = \frac{F_1}{A_1} = \frac{F_2}{A_2}

    where PP is pressure in Pa (N/m²), F1=200 NF_1 = 200\ \mathrm{N} is input force, A1A_1 is input piston area, A2A_2 is output piston area, and F2F_2 is output force in N.

  2. Calculate input piston area.

    Input diameter = 2 cm = 0.02 m, so radius r1=0.01 mr_1 = 0.01\ \mathrm{m}.

    A1=πr12A_1 = \pi r_1^2 A1=π(0.01)2=π×0.0001=3.14×10−4 m2A_1 = \pi (0.01)^2 = \pi \times 0.0001 = 3.14 \times 10^{-4}\ \mathrm{m^2}
  3. Calculate output piston area.

    Output diameter = 20 cm = 0.20 m, so radius r2=0.10 mr_2 = 0.10\ \mathrm{m}.

    A2=πr22A_2 = \pi r_2^2 A2=π(0.10)2=π×0.01=3.14×10−2 m2A_2 = \pi (0.10)^2 = \pi \times 0.01 = 3.14 \times 10^{-2}\ \mathrm{m^2}
  4. Find area ratio.

    A2A1=π(0.10)2π(0.01)2=0.010.0001=100\frac{A_2}{A_1} = \frac{\pi (0.10)^2}{\pi (0.01)^2} = \frac{0.01}{0.0001} = 100
  5. Calculate output force.

    F2=F1×A2A1F_2 = F_1 \times \frac{A_2}{A_1} F2=200 N×100=20000 NF_2 = 200\ \mathrm{N} \times 100 = 20000\ \mathrm{N}

    The output piston exerts 20000 N\boxed{20000\ \mathrm{N}} on the car door.

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