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A pulse of light with a speed of 3.0 x 108 m/s travels through a glass plate with a refractive index of 1.50 and a thickness of 0.9 cm. Calculate the time it takes for the light to pass through the pl

Physics

ScanSolve AI Answer

Answer

B

Step-by-step solution

3 steps

To find the time it takes for a pulse of light to pass through the glass plate, we first need to calculate the speed of light within the glass.

  1. Convert the thickness of the plate to meters.

    The thickness (dd) is given as 0.9 cm0.9 \text{ cm}.

    d=0.9 cm×1 m100 cm=0.009 m=9.0×10−3 md = 0.9 \text{ cm} \times \frac{1 \text{ m}}{100 \text{ cm}} = 0.009 \text{ m} = 9.0 \times 10^{-3} \text{ m}
  2. Calculate the speed of light (vv) in the glass plate.

    The refractive index (nn) is defined as the ratio of the speed of light in a vacuum (cc) to the speed of light in the medium (vv).

    n=cvn = \frac{c}{v}

    We are given n=1.50n = 1.50 and c=3.0×108 m/sc = 3.0 \times 10^8 \text{ m/s}.
    Rearrange the formula to solve for vv:

    v=cnv = \frac{c}{n} v=3.0×108 m/s1.50v = \frac{3.0 \times 10^8 \text{ m/s}}{1.50} v=2.0×108 m/sv = 2.0 \times 10^8 \text{ m/s}
  3. Calculate the time (tt) it takes for the light to pass through the plate.

    Time is calculated by dividing the distance (thickness of the plate) by the speed.

    t=dvt = \frac{d}{v} t=9.0×10−3 m2.0×108 m/st = \frac{9.0 \times 10^{-3} \text{ m}}{2.0 \times 10^8 \text{ m/s}} t=9.02.0×10−3−8 st = \frac{9.0}{2.0} \times 10^{-3-8} \text{ s} t=4.5×10−11 st = 4.5 \times 10^{-11} \text{ s}

    Comparing this result with the given options:
    A. 3.0×10−10 s3.0 \times 10^{-10} \text{ s}
    B. 4.5×10−11 s4.5 \times 10^{-11} \text{ s}
    C. 3.0×10−11 s3.0 \times 10^{-11} \text{ s}
    D. 4.5×10−10 s4.5 \times 10^{-10} \text{ s}

    The correct option is B.

    The time taken is:

    B. 4.5×10−11 s\boxed{\text{B. } 4.5 \times 10^{-11} \text{ s}}
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