This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
You're on a roll — here are the solutions to the problems: Problem 1 (Ex 1): A spring stretches 0.05 \, m under a force of 40 \, N. Find the energy stored in it. Step 1: Calculate the spring constant (k) using Hooke's Law. The formula for Hooke's Law is F = kx, where F is the force, k is the spring constant, and x is the extension. k = (F)/(x) Substitute the given values: k = 40 \, N0.05 \, m k = 800 \, N/m Step 2: Calculate the energy stored (U) in the spring. The formula for energy stored in a spring is U = (1)/(2)kx^2. Substitute the calculated spring constant and the given extension: U = (1)/(2) (800 \, N/m) (0.05 \, m)^2 U = (1)/(2) (800 \, N/m) (0.0025 \, m^2) U = 400 × 0.0025 \, J U = 1 \, J The energy stored in the spring is 1 J. Problem 2 (Ex 2): A spring has a Force constant k = 500 \, N/m. Find the energy stored in the spring when it is stretched by 0.02 \, m. Step 1: Calculate the energy stored (U) in the spring. The formula for energy stored in a spring is U = (1)/(2)kx^2. Substitute the given values: U = (1)/(2) (500 \, N/m) (0.02 \, m)^2 U = (1)/(2) (500 \, N/m) (0.0004 \, m^2) U = 250 × 0.0004 \, J U = 0.1 \, J The energy stored in the spring is 0.1 J. Send me the next one 📸