A travelling wave moving from left to right has an amplitude of 0.15m, a frequency of 550Hz and a wavelength of 0.01m. The equation describing the wave is A. y = 0.15 sin 200π(x - 5.5t) B. y = 0.15 sin π(0.01x - 5.5t) C. y = 0.15 sin 5.5π(x - 200t) D. y = 0.15 sin π(550x - 0.01t)

To find the equation describing the travelling wave, we use the general form for a wave moving from left to right: y(x, t) = A (kx - t) where A is the amplitude, k is the wave number, and is the angular frequency. Given values: Amplitude A = 0.15 \, m Frequency f = 550 \, Hz Wavelength = 0.01 \, m Step 1: Calculate the wave number k. The wave number k is given by the formula k = (2)/(). k = (2)/(0.01 \, m) = 200 \, rad/m Step 2: Calculate the angular frequency . The angular frequency is given by the formula = 2 f. = 2 (550 \, Hz) = 1100 \, rad/s Step 3: Substitute the values of A, k, and into the wave equation. y(x, t) = 0.15 (200 x - 1100 t) Step 4: Compare this equation with the given options. Let's examine option A: y = 0.15 200(x - 5.5t) Expand the term inside the sine function: 200(x - 5.5t) = 200 x - 200 × 5.5t 200 × 5.5 = 1100 So, option A becomes: y = 0.15 (200 x - 1100 t) This matches the equation we derived. The final answer is A.