A travelling wave moving from left to right has an amplitude of 0.15m, a frequency of 550Hz and a wavelength of 0.01m. The equation describing the wave is A. y = 0.15 sin 200π(x - 5.5t) B. y = 0.15 sin π(0.01x - 5.5t) C. y = 0.15 sin 5.5π(x - 200t) D. y = 0.15 sin π(550x - 0.01t)

The wave number $k$ is given by the formula $k = \frac{2\pi}{\lambda}$.

$$k = \frac{2\pi}{0.01 \, \text{m}} = 200\pi \, \text{rad/m}$$

The angular frequency $\omega$ is given by the formula $\omega = 2\pi f$.

$$\omega = 2\pi (550 \, \text{Hz}) = 1100\pi \, \text{rad/s}$$

Let's examine option A: $y = 0.15 \sin 200\pi(x - 5.5t)$
Expand the term inside the sine function:

$$200\pi(x - 5.5t) = 200\pi x - 200\pi \times 5.5t$$ $$200\pi \times 5.5 = 1100\pi$$

So, option A becomes:

$$y = 0.15 \sin(200\pi x - 1100\pi t)$$

This matches the equation we derived.

The final answer is $\boxed{\text{A}}$.