Here is the completed table: Step 1: Calculate R₁ for each row using Ohm's Law, R₁ = V_x/I. For the first row: R₁ = 1.5 V0.005 A = 300 Ω For the second row: R₁ = 3.0 V0.010 A = 300 Ω For the third row: R₁ = 4.5 V0.015 A = 300 Ω For the fourth row: R₁ = 6.0 V0.020 A = 300 Ω For the fifth row: R₁ = 7.5 V0.025 A = 300 Ω Step 2: Complete the table with the calculated values. V_x (V) — I (A) — R₁ = V_x/I (Ω)1.5 — 0.005 — 300 3.0 — 0.010 — 300 4.5 — 0.015 — 300 6.0 — 0.020 — 300 7.5 — 0.025 — 300

Complete the table

July 12, 2026Physics

ScanSolve AI Answer

Step-by-step solution

2 steps

Here is the completed table:

Calculate $R_1$ for each row using Ohm's Law, $R_1 = \frac{V_x}{I}$ .
For the first row:
$R_1 = \frac{1.5 \, \text{V}}{0.005 \, \text{A}} = 300 \, \Omega$
For the second row:
$R_1 = \frac{3.0 \, \text{V}}{0.010 \, \text{A}} = 300 \, \Omega$
For the third row:
$R_1 = \frac{4.5 \, \text{V}}{0.015 \, \text{A}} = 300 \, \Omega$
For the fourth row:
$R_1 = \frac{6.0 \, \text{V}}{0.020 \, \text{A}} = 300 \, \Omega$
For the fifth row:
$R_1 = \frac{7.5 \, \text{V}}{0.025 \, \text{A}} = 300 \, \Omega$
Complete the table with the calculated values.
$V_x$ (V) $I$ (A) $R_1 = \frac{V_x}{I}$ ( $\Omega$ )
1.5 0.005 300
3.0 0.010 300
4.5 0.015 300
6.0 0.020 300
7.5 0.025 300