This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Welcome back — been a while! Let's pick up where you left off. Here are the solutions to your questions: Question 1: Determine the quantity of charge flowed. Step 1: Convert the time from minutes to seconds. t = 15 minutes × 60 seconds1 minute = 900 seconds Step 2: Calculate the quantity of charge (Q) using the formula Q = I × t. Q = 15 A × 900 s Q = 13500 C The quantity of charge flowed is 13500 C. --- Question 2: Determine the mass of copper deposited. Assumption: The phrase "current of 5C" is interpreted as "current of 5A", as current is measured in Amperes (A) and charge in Coulombs (C). Step 1: Convert the time from minutes and seconds to total seconds. t = 15 minutes 33 seconds t = (15 × 60) s + 33 s t = 900 s + 33 s t = 933 s Step 2: Calculate the total charge (Q) passed using the formula Q = I × t. Q = 5 A × 933 s Q = 4665 C Step 3: Identify the necessary constants for copper deposition. • Molar mass of copper (M) = 63.55 g/mol • Valency of copper (n) = 2 (for Cu^2+ ions) • Faraday's constant (F) = 96485 C/mol Step 4: Apply Faraday's First Law of Electrolysis to find the mass (m) of copper deposited. m = (Q × M)/(n × F) m = 4665 C × 63.55 g/mol2 × 96485 C/mol m = 296400.75 g192970 m ≈ 1.536 g The mass of copper deposited is 1.536 g. Send me the next one 📸