This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
ScanSolve AI Answer
Another one I. — let's solve it. c) i) Natural radioactivity is the spontaneous disintegration of unstable atomic nuclei found in nature, without any external intervention. Induced radioactivity is the artificial creation of unstable atomic nuclei by bombarding stable nuclei with high-energy particles (like neutrons or protons), causing them to become radioactive. c) ii) Step 1: Identify the given values. Initial mass, N_0 = 0.600g Final mass, N_t = 0.395g Time elapsed, t = 10 years Step 2: Use the radioactive decay formula. The formula relating the remaining mass to the initial mass and half-life is: N_t = N_0 ((1)/(2))^t/T where T is the half-life. Step 3: Substitute the given values into the formula. 0.395g = 0.600g ((1)/(2))^10/T Step 4: Isolate the exponential term. (0.395)/(0.600) = ((1)/(2))^10/T 0.658333... = ((1)/(2))^10/T Step 5: Take the natural logarithm of both sides. (0.658333...) = (((1)/(2))^10/T) (0.658333...) = (10)/(T) ((1)/(2)) Step 6: Solve for T. We know that ((1)/(2)) = -(2). (0.658333...) = (10)/(T) (-(2)) T = (10 × (-(2)))/((0.658333...)) T = (-10 × 0.693147)/(-0.41800) T = (6.93147)/(0.41800) T ≈ 16.582 years The half-life of ^90Sr is approximately 16.6 years. 16.6 years What's next? Send 'em! 📸