Solve everything in the pic

Given:
Mass, $m = 2000 \text{ kg}$
Velocity, $v = 10 \text{ m/s}$
The formula for kinetic energy is $KE = \frac{1}{2}mv^2$.

The kinetic energy of the car is $\boxed{100000 \text{ J}}$.

Question 2, Part B:
The car then accelerates to 20 m/s. Calculate the increase in kinetic energy.

From Part A, initial kinetic energy ($KE_1$) when $v_1 = 10 \text{ m/s}$ is $100000 \text{ J}$.
For final kinetic energy ($KE_2$):
Mass, $m = 2000 \text{ kg}$
Final velocity, $v_2 = 20 \text{ m/s}$

The increase in kinetic energy is $\boxed{300000 \text{ J}}$.

Question 2, Part C:
If the car takes 5 seconds to accelerate from 10 m/s to 20 m/s, calculate the power developed by the engine.

Work done, $W = \Delta KE = 300000 \text{ J}$ (from Part B)
Time, $t = 5 \text{ s}$
The formula for power is $P = \frac{W}{t}$.

The power developed by the engine is $\boxed{60000 \text{ W}}$.

Question 3, Part A:
A 50 kg mass is lifted vertically by 10 m. Calculate the potential energy gained by the mass.

Given:
Mass, $m = 50 \text{ kg}$
Height, $h = 10 \text{ m}$
Acceleration due to gravity, $g = 9.8 \text{ m/s}^2$ (standard value)
The formula for potential energy is $PE = mgh$.

The potential energy gained by the mass is $\boxed{4900 \text{ J}}$.

Question 3, Part B:
If the mass is lifted in 2 seconds, calculate the power required.

Work done, $W = PE = 4900 \text{ J}$ (from Part A)
Time, $t = 2 \text{ s}$
The formula for power is $P = \frac{W}{t}$.

The power required is $\boxed{2450 \text{ W}}$.