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Given velocity field: V = (3x + 2y)i + (2z - 3x²)j + (2t - 3z)k

Physics

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Question 2b)
Given velocity field: V=(3x+2y)i+(2z−3x2)j+(2t−3z)k\mathbf{V} = (3x + 2y)\mathbf{i} + (2z - 3x^2)\mathbf{j} + (2t - 3z)\mathbf{k}

Step 1: Determine the velocity components u, v, and w.
The velocity vector is given by V=ui+vj+wk\mathbf{V} = u\mathbf{i} + v\mathbf{j} + w\mathbf{k}.
By comparing the given expression with the general form:

u=3x+2yu = 3x + 2y v=2z−3x2v = 2z - 3x^2 w=2t−3zw = 2t - 3z

These are the velocity components at

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