Define gravitational field

Physics

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Answer

g=Fgm(units:N/kgorm/s2)\vec{g} = \frac{\vec{F_g}}{m} (units: N/kg or m/s²)

Gravitational field

The gravitational field g\vec{g} at a point in space is defined as the gravitational force Fg\vec{F_g} exerted on a small test mass mm (with units kg) divided by that test mass.

Step 1: Formula
g=Fgm\vec{g} = \frac{\vec{F_g}}{m}

Step 2: Units
Gravitational field has units of newtons per kilogram (Nkg)\left( \frac{N}{kg} \right), equivalent to meters per second squared (m/s2)\left( m/s^2 \right).

Step 3: For a point mass MM
At a distance rr (units m) from point mass MM (units kg),
g=GMr2r^\vec{g} = -G \frac{M}{r^2} \hat{r}
where G=6.67430×1011m3kgs2G = 6.67430 \times 10^{-11} \, \frac{m^3}{kg \cdot s^2} is the gravitational constant (units m3kgs2\frac{m^3}{kg \cdot s^2}) and r^\hat{r} is the unit vector.

\vec{g = \frac{\vec{F_g}}{m}
(units: N/kg or m/s²)}

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