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Physics

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Answer

53m/s2\dfrac{5}{3} \mathrm{m/s^2}

Step 1: Identify the initial and final velocities with consistent units.

Initial velocity: u=0u = 0 km/h =0= 0 m/s

Final velocity: v=60v = 60 km/h =60×10003600=503= 60 \times \frac{1000}{3600} = \frac{50}{3} m/s 16.67\approx 16.67 m/s

Time: t=10t = 10 s

Step 2: Acceleration formula.

a=vuta = \frac{v - u}{t}

Step 3: Substitute values.

a=503010=503×10=5030=531.67a = \frac{\frac{50}{3} - 0}{10} = \frac{50}{3 \times 10} = \frac{50}{30} = \frac{5}{3} \approx 1.67 m/s²

Final answer: 53m/s2\boxed{\dfrac{5}{3} m/s^2}

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