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Identify the initial and final magnetic flux.

Physics

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Answer

8 V\text{8 V}

Step-by-step solution

3 steps

3.

  1. Identify the initial and final magnetic flux.

    Initial magnetic flux Φ1=80 µWb\Phi_1 = 80 \text{ µWb}.
    Since the flux is reversed, the final magnetic flux Φ2=−80 µWb\Phi_2 = -80 \text{ µWb}.

  2. Calculate the change in magnetic flux ΔΦ\Delta \Phi.

    ΔΦ=Φ2−Φ1=(−80 µWb)−(80 µWb)\Delta \Phi = \Phi_2 - \Phi_1 = (-80 \text{ µWb}) - (80 \text{ µWb}) ΔΦ=−160 µWb=−160×10−6 Wb\Delta \Phi = -160 \text{ µWb} = -160 \times 10^{-6} \text{ Wb}
  3. Apply Faraday's Law of Induction, E=−NΔΦΔt\mathcal{E} = -N \frac{\Delta \Phi}{\Delta t}.

    Given N=500N = 500 turns and Δt=0.01 s\Delta t = 0.01 \text{ s}.

    E=−(500)×−160×10−6 Wb0.01 s\mathcal{E} = -(500) \times \frac{-160 \times 10^{-6} \text{ Wb}}{0.01 \text{ s}} E=(500)×160×10−60.01 V\mathcal{E} = (500) \times \frac{160 \times 10^{-6}}{0.01} \text{ V} E=500×160×10−4 V\mathcal{E} = 500 \times 160 \times 10^{-4} \text{ V} E=80000×10−4 V\mathcal{E} = 80000 \times 10^{-4} \text{ V} E=8 V\mathcal{E} = 8 \text{ V}

    The induced EMF is 8 V\text{8 V}.

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