This physics problem tests your understanding of fundamental physical laws and their applications. The step-by-step solution below breaks down the problem using relevant equations and physical reasoning.
Calculate the kinetic energy of a body of mass 100 kg moving with a speed of 2 m/s. Write the definition of momentum and the relationship between momentum, mass, and velocity, and the relationship between momentum, force, and time, and the relationship between momentum, pressure, and area.
Physics

ScanSolve AI Answer
20) i) A र B वस्तुहरु बिचको गुरुत्वाकर्षण बल पत्ता लगाउनुहोस्। Assumption: वस्तु A को पिण्ड kg र अर्धव्यास m दिइएको छ। kg पिण्ड पृथ्वीको पिण्डसँग मिल्दोजुल्दो छ। पृथ्वीको अर्धव्यास लगभग km हुन्छ। त्यसैले, यहाँ m लाई km मानिएको छ, अर्थात् m। वस्तु B वस्तु A को सतहमा छ भनी मानिएको
Was this helpful?
Still stuck on this one?
Ask a follow-up, and the answer starts from this question.
Got a different question?Ask your own question
More Physics Questions
QA body of mass 2.0 kg starts from rest and moves through a distance of 5m with a uniform velocity of…QCalculate the kinetic energy of a 2 kg object moving at 3 m/sQCalculate the potential energy of a 50 kg body at a height of 1.5 m, and its kinetic energy if it mo…QRelate kinetic energy and momentum.QA body of mass 100 g moving at 10 m/s collides and rebounds with a speed of 2 m/s. Calculate the cha…

Handwritten Step-by-Step Solution
Get this as a handwritten image on WhatsApp — like a tutor wrote it for you.
Try on WhatsAppScanSolve AI Answer
20) i) A र B वस्तुहरु बिचको गुरुत्वाकर्षण बल पत्ता लगाउनुहोस्। Assumption: वस्तु A को पिण्ड 6 × 10^24 kg र अर्धव्यास 6400 m दिइएको छ। 6 × 10^24 kg पिण्ड पृथ्वीको पिण्डसँग मिल्दोजुल्दो छ। पृथ्वीको अर्धव्यास लगभग 6400 km हुन्छ। त्यसैले, यहाँ 6400 m लाई 6400 km मानिएको छ, अर्थात् R_A = 6.4 × 10^6 m। वस्तु B वस्तु A को सतहमा छ भनी मानिएको