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Make g the subject of the formula: E = mv2/2 + mgh

June 3, 2026Physics

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Answer

g = \frac{2E - MV^2}{2mh}

3 steps

To make $g$ the subject of the formula $E = \frac{MV^2}{2} + mgh$ :

Subtract $\frac{MV^2}{2}$ from both sides of the equation to isolate the term containing $g$ .
$E - \frac{MV^2}{2} = mgh$
To combine the terms on the left side, find a common denominator.
$\frac{2E}{2} - \frac{MV^2}{2} = mgh$ $\frac{2E - MV^2}{2} = mgh$
Divide both sides by $mh$ to solve for $g$ .
$g = \frac{2E - MV^2}{2mh}$

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