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Which of the following statement is not a real life example of Newton's first law?

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14. Which of the following statement is not a real life example of Newton's first law?
Newton's First Law (Law of Inertia) describes how objects resist changes in their state of motion.

  • A. When a bus suddenly starts, passengers fall backward due to inertia of rest. This is an example.
  • B. A rider thrown forward when a horse stops suddenly is due to inertia of motion. This is an example.
  • C. Fruits falling when a branch is shaken is due to inertia of rest. This is an example.
  • D. When a bus suddenly starts, passengers tend to fall backward, not forward. Falling forward occurs when a bus stops suddenly. Therefore, this statement is not a correct example of Newton's first law in the described scenario.

The correct option is D\boxed{\text{D}}.

15. Vehicle accelerates uniformly from rest at 5 m/s25 \text{ m/s}^2. What is the velocity after 5 s5 \text{ s}?

  1. Identify the given values.

    Initial velocity u=0 m/su = 0 \text{ m/s} (from rest)
    Acceleration a=5 m/s2a = 5 \text{ m/s}^2
    Time t=5 st = 5 \text{ s}

  2. Use the kinematic equation v=u+atv = u + at.

    v=0 m/s+(5 m/s2)(5 s)v = 0 \text{ m/s} + (5 \text{ m/s}^2)(5 \text{ s})

  3. Calculate the final velocity.

    v=25 m/sv = 25 \text{ m/s}

    The velocity after 5 s5 \text{ s} is A. 25 m/s\boxed{\text{A. } 25 \text{ m/s}}.

    16. An object from rest accelerates at 4 m/s24 \text{ m/s}^2 for 10 s10 \text{ s}. Calculate the Final velocity and distance travelled respectively.

  4. Identify the given values.

    Initial velocity u=0 m/su = 0 \text{ m/s} (from rest)
    Acceleration a=4 m/s2a = 4 \text{ m/s}^2
    Time t=10 st = 10 \text{ s}

  5. Calculate the final velocity using v=u+atv = u + at.

    v=0 m/s+(4 m/s2)(10 s)v = 0 \text{ m/s} + (4 \text{ m/s}^2)(10 \text{ s}) v=40 m/sv = 40 \text{ m/s}

  6. Calculate the distance travelled using s=ut+12at2s = ut + \frac{1}{2}at^2.

    s=(0 m/s)(10 s)+12(4 m/s2)(10 s)2s = (0 \text{ m/s})(10 \text{ s}) + \frac{1}{2}(4 \text{ m/s}^2)(10 \text{ s})^2 s=0+12(4 m/s2)(100 s2)s = 0 + \frac{1}{2}(4 \text{ m/s}^2)(100 \text{ s}^2) s=2 m/s2×100 s2s = 2 \text{ m/s}^2 \times 100 \text{ s}^2 s=200 ms = 200 \text{ m}

    The final velocity is 40 m/s40 \text{ m/s} and the distance travelled is 200 m200 \text{ m}.

    The correct option is A. 40 m/s and 200 m\boxed{\text{A. } 40 \text{ m/s and } 200 \text{ m}}.

    17. A force of 100 N100 \text{ N} acts on a mass of 50 kg50 \text{ kg}. Find the acceleration of the body.

  7. Identify the given values.

    Force F=100 NF = 100 \text{ N}
    Mass m=50 kgm = 50 \text{ kg}

  8. Use Newton's Second Law of Motion, F=maF = ma.

    100 N=(50 kg)×a100 \text{ N} = (50 \text{ kg}) \times a

  9. Solve for acceleration aa.

    a=100 N50 kga = \frac{100 \text{ N}}{50 \text{ kg}} a=2 m/s2a = 2 \text{ m/s}^2

    The acceleration of the body is A. 2 m/s2\boxed{\text{A. } 2 \text{ m/s}^2}.

    18. The rate of change of displacement with time is known as...
    The rate of change of displacement with time is the definition of velocity.

    The correct option is D. Velocity\boxed{\text{D. Velocity}}.

    19. The word LASER is an acronym representing
    LASER stands for Light Amplification by Stimulated Emission of Radiation.

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